Parašė kiskiss· 2007 Lie. 27 12:07:39
#5
Tegul jis daro ka nori.
Kai pabaigsi rasyti naujienas apacioje dar darasyk:
<html>
<body>
<form action="upload_file.php" method="post"
<label for="file">Ikelti paveiksliuka:</label>
<input type="file" name="file" id="file" />
<br />
<input type="submit" name="submit" value="Ideti" />
</form>
</body>
</html>
irašyk kad leistu įkelti .jpeg ir .jpg failus ne didesnius nei 20kb. Failas dabar turi atrodyti maždaug taip:
<?php
if (($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/pjpeg")
&& ($_FILES["file"]["size"] < 20000))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"]))
{
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
}
else
{
echo "Invalid file";
}
?>
upload_file.php ikelk i savo pagrindine direktorija kur yra visi failai.
Ir dar sukurk upload folderi ir suchmodink i 777
Bet kaip minejo gali ideti shella su uzkrestu paveiksliuku. Tai tavo svetaine bus labai pazeidziama
Redagavo kiskiss· 2007 Lie. 27 13:07:31